Question

y' = (x-10)^2+(x+1)*(2x-20)

Answer 1

$frac{dy}{dx} =(x-10)^2+(x+1)(2x-20)\ \int {y} , dy =int{(x^2-20x+100+2x^2+2x-20x-20)dx}\ \ y=int{(3x^2-38x+80)}dx=x^3-19x^2+80x+C$