Question

Lim при x стремящимся к 3 дробь х^2-9/х^2-7х+12

Answer 1

$lim_{x to 3} frac{x^2-9}{x^2-7x+12} = frac{9-9}{9-21+12} = frac{0}{0} = frac{(x-3)(x+3)}{(x-4)(x-3)} \ = frac{6}{-1} = -6$