Question

Вычислить:
1) 2arctg1-3arcsin√32
2) cos(6arccos√22)
3) ctg(arctg√3)
4) sin(arctg(-√3))
5) cos(arctg 1)

Answer 1

1) 2arctg1-3arcsin√32=2*π/4-3*π/3=π/2-π=-π/2
2) cos(6arccos√22)=6*π/4=3π/2
3) ctg(arctg√3)=1√3
4) sin(arctg(-√3))=-√3/√(1+3)=-√3/2
5) cos(arctg 1) =1/√(1+1)=1/√2