Question

(x-3)^2+(3-x)(x+3)=(x+2)^2-x^2 решите уравнение

Answer 1

$(x-3)^2+(3-x)(x+3)=(x+2)^2-x^2\x^2-6x+9+9-x^2=x^2+4x+4-x^2\-6x+18=4x+4\-6x-4x=4-18\-10x=-14\x=-14:(-10)\x=1,4$