Question

0,4/(log25 100 - log5 2) в 4 степени

Answer 1

$0,4:(log_{25}100-log_52)=0,4:(log_{5^2}(10^2)-log_52)=\\=0,4:(frac{1}{2}cdot 2cdot log_5(5cdot 2)-log_52)=0,4:(1+log_52-log_52)=\\=0,4:1=0,4$