Question

Вычислите: a)lim n2-2n+2/3n2+6n+12 б)limx2-6x+9/x2-3x x-->3

Answer 1

$limlimits_n dfrac{n^2-2n+2}{3n^2+6n+1}=dfrac13$

$limlimits_{xto3} dfrac{x^2-6x+9}{x^2-3x}=limdfrac{(x-3)^2}{x(x-3)}=limdfrac{x-3}{x}=0$