Question

Решите уравнение: (1-2x)^4-5(1-2x)^2=-4

Answer 1

$(1-2x)^4 - 5(1-2x)^2 = - 4 16x^4 - 32x^3 + 4x^2 + 12x - 4 = -4 16x^4 - 32x^3 + 4x^2 + 12x = 0 4x(x - 1)(2x - 3)(2x + 1) = 0 x(x - 1)(2x - 3)(2x + 1) = 0 x - 1 = 0 ; x = 0 ; 2x - 3 = 0 ; 2x + 1 = 0 x1 = 1 ; x2 = 0 ; x3 = 1,5 ; x4 = -0,5$

Answer 2

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