Question

Запишите в виде паскаля.

1) y=√a-c²/sin(x-a²)

2) y=√c/x-a²+3π

3) y=3b-a/8(c+2)-√5b-8c+3π

4) p=√(x²-x¹)²+(y²-y¹)²

Answer 1

1)y:=sqrt(a)-sqr(c)/sin(x-sqr(a))
2)y:=sqrt(c)/x-sqr(a)+3*pi
3)y:=3*b-1/8*(c+2)-sqrt(5*b)-8*c+3*pi
4)p:=sqrt(sqr(sqr(x)-x)+sqr(sqr(y)-y))