Question

m^6+m^4+m^2+1            сократить дробь ПОМОГИТЕ ПЛИЗ

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m^3+m^2+m+1

Answer 1

$frac{m^6+m^4+m^2+1}{m^3+m^2+m+1}=frac{m^4(m^2+1)+(m^2+1)}{m^2(m+1)+(m+1)}=frac{(m^2+1)(m^4+1)}{(m+1)(m^2+1)}=frac{m^4+1}{m+1}$

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Answer 2

$frac{m^6+m^4+m^2+1}{m^3+m^2+m+1}=\frac{m^4(m^2+1)+(m^2+1)}{m^2(m+1)+(m+1)}=\frac{(m^2+1)(m^4+1)}{(m^2+1)(m+1)}=\frac{m^4+1}{m+1}$