Question

решите уравнение
sin 3x =1/2

Answer 1

3х=t
sint=1/2
t=$left { {{arcsin 1/2 + 2 pi n} atop {П-arcsin 1/2 + 2 pi Пn}} right.$ n∈z
t=$left { {{ pi/6 + 2 pi n} atop {5 pi /6 +2 pi n}} right.$ n∈z