Question

(x^2-1)^2 (x^2-6x-7)^2=0

Answer 1

$(x^2-1)^2 (x^2-6x-7)^2=0 \ \ (x^2-1) (x^2-6x-7)=0 \ \ (x-1)(x+1) (x^2-7x+x-7)=0 \ \ (x-1)(x+1) (x-7)(x+1)=0 \ \ x_{1} =1;x_{2} =-1;x_{3} =7 \ \ otvet:{1;-1;7}$