Question

-2+2^x+2^2x=0 решите пожалуйста

Answer 1

$-2+2^x+2^2x=0 \ t = 2^x \ -2+t+t^2=0 ; t^2+t-2=0 \ D = 1-4*1-2= 9 \ t_1, t_2 = frac{-1+-3}{2} \ t_1 = 1 ; t_2 = -2 \ 2^x = 1 ; x = 0 \ 2^x = -2; \ 2^x textgreater 0 \ Not-solution\ \ Answer: x = 0$