Question

log2(2x-1)-2=log2(x+2)-log2(x+1).Помогите

Answer 1

$log_2^{2x-1}-2=log_2^{x+2}-log_2^{x+1} = \ = log_2^{(2x-1):4)}= log_2^{x+2}-log_2^{x+1}\ frac{2x-1}{4} = x+2-x+1 \ frac{2x-1}{4} = 3 \ 2x-1 = 12 \ 2x = 13 |:2 \ x = 7.5$