Question

пОМОГИТЕ,СРОЧНО ЛЮДИ(((

Answer 1

$4x^4-17x^2-15=0 \ t = x^2 \ 4t^2-17t-15=0 \ D = 289-4*4*-15 = 529 \ x_1,x_2 = frac{17+-23}{8} \ t_1 = 5 ; t_2 = -6/8 \ x^2 = 5 ; t_2 = wrong-answer textless 0. \ x = +-sqrt{5}$
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$3x-(2x-7) leq 3(1+x) \ 3x-2x+7 leq 3+3x \ 7-3 leq 5x-3x \ 4 leq 2x |:2 \ 2 leq x$
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$left { {{3x+17 textless 2} atop {3-4x textless 19}} right. \ 3x textless -15 |:3 \ x textless -5 \ 3-4x textless 19 \ 3-19 textless 4x \ -16 textless 4x |:4 \ -4 textless x \ Answer: there-is-no-solution$$frac{x+3}{7} = frac{2-x}{3} \ 3(x+3) = 7(2-x) \ 3x+9=14-7x \ 10x = 5 |:10 \ x = 0.5$
$(x-1/3)(x-1/5) leq 0 \ x = 1/3 ; x = 1/5 \ 1/5 leq x leq 1/3$