Question

Решите уравнение
2tg0+8sin$frac{3pi}{2}$-6cos$frac{2Pi}{3}$
Pi-П

Answer 1

$2tg0+8sinfrac{3pi}{2}-6cosfrac{2pi}{3}=2tg0+8sinfrac{3pi}{2}-6cos(frac{pi}{2}+frac{pi}{6})=\=2tg0+8sinfrac{3pi}{2}+6sinfrac{pi}{6}=2*0+8*(-1)+6*frac12=0-8+3=-5$