Предмет: Химия, автор: dimanchik33

Относительная плотность газа по воздуху равна 1,31. Его объем равен 168 л. Определить массу газа при н.у.

Ответы

Автор ответа: matmat1982

0

М газа = 1,31*29 =38 г/моль (по формуле Мгаза/Мвоздуха = 1, 31, М воздуха =29 г/моль)

n(газа) =168л/22,4 л/моль = 7,5 моль

m(газа) = 7,5 моль*38 моль = 285 г

Автор ответа: dimanchik33

0

Спасибо большое)))

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