Question

хелп ми плиз tg^2x+3tgx=0 уравнение log'3(x-2)+log'3(x+6)=2

Answer 1

$tg^2x+3tg x=0\ tg x(tg x+3)=0\ begin {cases} tg x =0\ tg x +3=0\ end {cases}\ \ begin {cases} x =pipmpi n\ tg x=-3\ end {cases}\ \ begin {cases} x =pipmpi n\ x=-0,4pipmpi n\ end {cases}\ \ \ log_3(x+6)=2\ log_3(x+6)=log_39\ x+6=9\ x=3$