Question

x^3+4x^2-4x-16=0
подробно

Answer 1

$x^{3}+4 x^{2} -4x-16=0 \ x^{2} (x+4) -4(x+4)=0 \ (x+4)( x^{2}-4)=0 \ x+4=0 \ x_{1} =-4 \ x^{2}-4 =0 \ x^{2}=4 \ x= sqrt{4} \ x_{2}=2 \ x_{3} =-2$