Question

a)2/7x^2y*3/4x^3*7y^2 Б)(2m^3n^4)^3*5m^2n

Answer 1

$frac{2}{7}x^2y*frac{3}{4}x^3*7y^2=frac{2*3*7}{7*4}x^{2+3}y^{1+2}=frac{3}{2}x^5y^3;$

 

$(2m^3n^4)^3*5m^2n=8m^9n^{12}*5m^2n=40m^{11}n^{13}$