Question

lim x→0 (8x^3 - 2x^2 + 1) / (4x^3 + 3x^2 - 1)

Answer 1

$lim_{x->0} frac{8x^3-2x^2+1}{4x^3+3x^2-1}=\ lim_{x->0} frac{8-frac{2}{x}+frac{1}{x^3}}{4+frac{3}{x}-frac{1}{x^3}}=\ frac{8-0+0}{4+0-0}=2$