Question

y²-4=0 121-x²=0 1.96-y²=0 решите прошу

Answer 1

$y^2 - 4 = 0 (y - 2)(y + 2) = 0 y1 = 2 ; y2 = -2$

$121 - x^2 = 0 (x - 11)(x + 11) = 0 x1 = 11 ; x2 = -11$

$1,96 - y^2 = 0$
$frac{49}{25} - y^2 = 0$
$- frac{1}{25} (5y - 7)(5y + 7) = 0 (5y - 7)(5y + 7) = 0$
$y1 = frac{7}{5}$
$y2 = -frac{7}{5} y1 = 1,4 ; y2 = -1,4$