Предмет: Химия, автор: Vadm

Вычислите объем кислорода, необходимый для полного сгорания 10 л метана (CH4).Какой объем углекислого газа выделится при этом?

Ответы

Автор ответа: Indian

0

CH4+2O2=CO2+2H2O

n CH4=10/22.4=0.45 моль

n O2=0.45*2=0.89 моль

V O2=0.89*22.4=19.94 л

V CO2=0.45*22.4=10 литиров

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