Question

Привет,помоги решить систему уравнений
{3x-2y=6
{x2-4y=4

Answer 1

Постарайся проверить...

Answer 2

$left { {{3x-2y=6;} atop {x^2-4y=5;}} right.\ 2y=3x-6;\ y=1.5x-3;\ x^2-4(1.5x-3)=5;\ x^2-6x+12-5=0;\ x^2-6x+7=0;\ D=(-6)^2-4*1*7=36-28=8;\ x_1=frac{6+2sqrt{2}}{2*1}=3+sqrt{2};\ x_2=3-sqrt{2};\ y_1=1.5*(3+sqrt{2})-3=1.5+1.6sqrt{2};\ y_2=1.5*(3-sqrt{2})-3=1.5-1.5sqrt{2};\ (3+sqrt{2};1.5+1.5sqrt{2}), (3-sqrt{2}; 1.5-1.5sqrt{2})$