Question

3y-3y^3=y^2-y^4 Решите уравнение

Answer 1

$3y-3y^3 = y^2 - y^4 y^4-3y^2 - y^2 + 3y = 0 y*(y-3)(y-1)(y+1) = 0 y - 3 = 0 ; y - 1 = 0 ; y = 0 ; y + 1 = 0 y1 = 3 ; y2 = 1 ; y3 = 0 ; y4 = -1$