Question

Сможете?
Тригонометрическая

Answer 1

$ctg x-3=0\ ctg x=3\ x=arctg frac{1}{3}+pi n, n in mathbb Z \ x= frac{pi}{12}+pi n, nin mathbb Z$


$sin^2{4x}-cos^2{4x}=0\\ frac{sin^2{4x}}{cos^2{4x}} - frac{cos^2{4x}}{cos^2{4x}}=0\\ tg^2{4x}-1=0\\ tg^2{4x}=1\\ frac{1-cos8x}{cos 8x+1}=1\\ 1-cos 8x=cos 8x+1\\ -cos 8x-cos 8x=0\\ -2cos 8x=0\\ 8x= frac{pi}{2}+2pi n, n in mathbb Z \\ x= frac{pi}{16}+ frac{2pi n}{8}, n in mathbb Z\\ x_1= frac{pi}{16}+ frac{pi n}{4}, n in mathbb Z\\ x_2=-frac{pi}{16}+ frac{pi n}{4}, n in mathbb Z$