Question

1)$x^{2}-2x-8$
2)$y^{2}+2y-8$

Answer 1

1)x²-2x-8=0
D=4+4*8=6²
x1=2+6/2=4
x2=2-6/2=-2
x²-2x-8=(x-4)(x+2)
2)y²+2y-8=0
D=4+4*8=6²
y1=-2+6/2=2
y2=-2-6/2=-4
y²+2y-8=(y-2)(y+4)