Question

Напишите пожалуйста как решать такое☺️

Answer 1

№102
4√2cos(π/4)-cos(7π/3)=4√2*(√2/2)-1/2=3.5
cos(π/4)=√2/2,            cos(7π/3)=cos(2π+π/3)=cosπ/3=1/2
№103
60/(sin(-32π/3)cos(25π/6)=60/(-√3/2*√3/2)=-(60*4)/3=-80
sin(-32π/3)=-sin(10π+2π/3)=-sin(2π/3)=-sin(π-π/3)=-sinπ/3=-√3/2
cos(25π/6)=cos(4π+π/6)=cosπ/6=√3/2