Question

sin L=⅓ cos L=? tg L=?

Answer 1

$sin^{2}L + cos^{2}L =1$
$cosL= +-sqrt{1- sin^{2}L }$
$cosL=+- frac{2 sqrt{2} }{3}$
$tgL= frac{sinL}{cosL}$
$tgL= +- frac{1*3}{3*2 sqrt{2} } = +-frac{1}{2 sqrt{2} }$