Question

Помогите решить уравнение!)
36*16^x - 91*12^x + 48*9^x = 0

Answer 1

36*16^x - 91*12^x + 48*9^x = 0 /9^x
36*(16/9)^x-91*(4/3)^x+48=0
(4/3)^x=a
36a²-91a+48=0
D=8281-6912=1369
√D=37
a1=(91-37)/72=3/4⇒(4/3)^x=3/4⇒x=-1
a2=(91+37)/72=16/9⇒(4/3)^x=16/9⇒x=2