Question

помогите пожалуйста решить уравнения

Answer 1

1) 3^x=9^(x+1)
3^x=3^2(x+1)
x=2(x+1)
x=2x+2
x-2x=2
x=2
2)7^1-4x=1
7^1-4x=7^0
1-4x=0
-4x=0-1
-4x=-1
x=-1/4
3)3^x^2 -4x=9
3^x^2 -4x=3^2
x^2-4x=2
x(x-4)=2
x=2 или x-4=2
             x=2+4
             x=6
4)2^2x=2
2^2x=2^1
2x=1
x=1/2
5)2^x=16
2^x=2^4
x=4
6)2^x=32
2^x=2^5
x=5

Answer 2

В первом x=2x+2, x-2x=2,-x=2,x=-2

Answer 3

6)
2^x = 32
2^x = 2^5
x=5

5)
2^x =16
2^x =2^4
x = 4

4)
2^(2x) = 2
2^(2x) = 2^1
2x = 1
x = 1/2

1)
3^x = 9^(x+1)
3^x =3^(2(x+1))
x = 2(x+1)
x =2x + 2
– x = 2
x = – 2

2)
7^(1–4x) = 1
7^(1–4x) 7^0
1–4x = 0
– 4x = – 1
x = 1/4

3)
3^ (x^2–4x) = 9
3^ (x^2–4x) = 3^2
x^2 – 4x = 2
x^2 – 4x – 2 = 0
D = 16–4*(–2)=16+8=24
√24 = √(4*6) = 2√6

x1 = (4+2√6)/2 = 2+√6
x2 = (4–2√6)/2 = 2–√6