Предмет: Алгебра, автор: marina244

При каких значениях Х верно равенство? (3x+10)^2=3х+10

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Автор ответа: moboqe

$(3x+10)^2=3x+10 \ 9x^2+60x+100-3x-10=0 \ 3x^2+19x+30=0 \ D=361-360=1 \ x1=(-19+1)/6=-3 \ x2=(-19-1)/6=-20/6$

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