Question

(-с-3)(с+1) (11а-4)(3-2а) (х-t)(x2+2xt-3t2) x2 и t2- это степени

Answer 1

$(-c-3)(c+1)=-c^2 -c-3c-3=-c^2 -4c-3$

$(11a-4)(3-2a)=33a-22a^2-12+8a=-22a^2+41a-12$

$(x-t)(x^2+2xt-3t^2)=x^3+2x^2t-3xt^2-tx^2-2xt^2+3t^3=x^3+x^2t-5xt^2+3t^2$