Question

Решите неравенства
$1) sqrt[3]{x+2} leq -5$
$2) sqrt{2x+1} textgreater 8$
$3)(x-12) sqrt{x-3} leq 0$

Answer 1

1) $x+3leq (-5)^{3}= -125;quad xleq-128$

2) $2x+1 textgreater 8^2=64,quad 2x textgreater 63;quad x textgreater 31,5$

3) $left { {{x-12leq0,} atop {x-3geq0,}} right. left { {{xleq12} atop {xgeq3}} right., 3leq xleq12$

Answer 2

Благодарю