Question

Log6^9+2log6^2/log2^16-log1/3^9

Answer 1

=$frac{log _{6}9+log _{6}2^2 }{4+2} = frac{log _{6}9*4 }{6}= frac{log _{6} 36}{6} = frac{2}{6}= frac{1}{3}$

Answer 2

$(log(6)9+log(6)4)/(log(2)16-log(1/3)9)=log(6)(9*4)/(4+2)=$$log(6)36/6=2/6=1/3$