Question

Помогите x^2+16x+64=0

Answer 1

$x^{2} +16x+64=0 \ D=b^2-4ac=256-256=0 \ x_1= frac{-b+D}{2a} = frac{-16+0}{2} =-8 \ x_2= frac{-b-D}{2a} = frac{-16-0}{2} =-8$