Question

Решить систему уровнений х^2+y^2=2.5xy x-y=0.25xy

Answer 1

х^2+y^2=2.5xy

x-y=0.25xy

 

(x-y)(x+y)=2.5xy

  x-y=0.25xy

тогда я получаю

0.25xy(x+y)=2.5xy

x+y=2.5xy/0.25xy

x+y=10

x=10-y

(10-y)^2+y^2=2.5y(10-y)

100-20y-y^2=25y-2.5y^2

4.5y^2-45y+100=0     /5

0.9y^2-9y+20=0 

D=81-72=9 

 y1=12/1.8=6(2/3)           x1=10-6(2/3)=3(1/3) 

y2=3(1/3)                     x2=10-3(1/3)= 6(2/3)

 

ответ:  х1=3(1/3)      у1= 6(2/3)  

            х2=  6(2/3)       у2=  3(1/3)