Question

Срочно нужно решить!
$left { {{x+3y=10} atop {xy=3}} right.$

Answer 1

х=10-3у
(10-3у)у=3
$10y-3 y^{2} -3=0 \ 3 y^{2} -10 +3=0 \ D=b^{2} -4ac=100-36=64= 8^{2} \ y_{1} =(10+8)/6=3 \ y_{2} =(10-8)/6=1/3$