Question

Найти производную (x^2+3)(x^4-1)

Answer 1

$y= (x^2+3)cdot(x^4-1) \ y'=(x^2+3)'cdot(x^4-1)+(x^4-1)'cdot(x^2+3)= \ =2xcdot(x^4-1)+4x^3cdot(x^2+3)=2x^5-2x+4x^5+12x^3= \ =6x^5+12x^3-2x=2x(3x^4+6x^2-1)$