Question

Sin (п/6 - x)
найдите производную

Answer 1

y =sin(π/6 -x) ;  || y =sin(-(x-π/6)) = -sin(x-π/6)⇒y ' =(-sin(x-π/6))' = -cos(x-π/6) ||
y ' =(sin(π/6 -x)) ' =cos((π/6 -x)*(π/6 -x)' =cos((π/6 -x)*(π/6)' -x')=cos((π/6 -x)*(0 -1) .
y ' = - cos(π/6 -x)= -cos(x-π/6).