Question

sqrt(3)-sqrt(6)*cosx=0

Answer 1

√3 - √6 * cos x = 0

√6 * cos x = √3

cos x = √3 / √6

cos x = √(3/6)

cos x = √(1/2)

cos x = 1 / √2

x = ± arccos 1/√2 + 2pi n,    n e Z

x= ± pi/4 + 2pi n,      n e Z

Answer 2

$sqrt3-sqrt6*cosx=0 \ sqrt6*cosx=sqrt3 \ sqrt2*cosx=1 \ cosx=frac{1}{sqrt2} \ \ x=бfrac{pi}{4}+2pi*n, n in Z$