Question

Помогите решить.а) (1/64)^х. =корень1/8. Б) 2^х+3 - 2^х=112. В)............. 7^2х-6*7^х+5=0. Г)(1/3)^х < 1/8

Answer 1

1)1/8^2X=КОРЕНЬ1/8             2)2^X*2^3-1*2^X=112
2X=1/2                                      7*2^X=112
X=0,25                                      2^X=112/7
                                                2^X=16
                                                X=4
3)ПУСТЬ 7^X=T,ТОГДА          4)НЕ ЗНАЮ
T^2-6T+5=0
D=36-20=16
X1=5  X2=1