Question

Помогите пожалуйста: 1396 (а б) 1397 аб 1398 бв

Answer 1

1396а
$2^x geq 4 \ 2^x geq 2^2 \ x geq 2$

1396б
$2^x textless frac{1}{2} \ 2^x textless 2^{-1} \ x textless -1$

1397а
$3^x leq 81 \ 3^x leq 3^4 \ x leq 4$

1397б
$( frac{1}{3} )^x textgreater frac{1}{27} \ ( frac{1}{3} )^x textgreater ( frac{1}{3} )^3 \ x textless 3$

1398б
$( frac{2}{3} )^{3x+6} textgreater frac{4}{9} \ ( frac{2}{3} )^{3x+6} textgreater ( frac{2}{3} )^2 \ 3x+6 textless 2 \ 3x textless -4 \ x textless - frac{4}{3}$

1398в
$5^{4x+2} geq 125 \ 5^{4x+2} geq 5^3 \ 4x+2 geq 3 \ 4x geq 1 \ x geq frac{1}{4}$