Question

решите уравнение 3x^3-2x^2-x=0

Answer 1

x (3x^2 - 2x - 1) =0

# 1
x1 = 0 

#2 
3x^2 - 2x - 1 = 0 
D = 4 + 4*3 = 16 
x2 = ( 2 + 4)/6 = 1;
x3 = ( 2 - 4)/6 = - 2/6 = - 1/3 

Ответ
- 1/3; 0; 1 

Answer 2

$3x^3-2x^2-x=0 \ x(3x^2-2x-1)=0 \ x=0 \ Delta=4+12=16 \ x= frac{2-4}{2*3}=- frac{1}{3} \ x= frac{2+4}{2*3}=1$