Question

Помогите с математикой, пожалуйста.

Answer 1

А
=x^3/5·x^1/2 = x^(3/5 + 1/2) = x^11/10
Б
=x^0,5:x^0,5 = x^0 =1
A
=x^0,9·x^1,1 = x^2
Б
= x^1/6 ^ x:1/2 = x^(1/6 - 1/2) = x^-2/6 = х^-1/3

Answer 2

$sqrt[10]{x^9} *x^{1.1}=x^{ frac{9}{10}+ frac{11}{10}}=x^{ frac{20}{10}}=x^2\\ frac{ sqrt[6]{x} }{ sqrt{x} }=x^{ frac{1}{6}- frac{1}{2}}= x^{-frac{2}{6}}=x^{- frac{1}{3}}= frac{1}{ sqrt[3]{x} }$