Question

система уравнений

x+y=2

x^2-2y=12

Answer 1

$x+y=2;x^2-2y=12$

$y=2-x;$

$x^2-2(2-x)=12;\x^2+2x-4=12;\x^2+2x-4-12=0;\ x^2+2x-16=0; D=2^2-4*1*(-16)=4+64=68;\ x_1=frac{-2+2sqrt{17}}{2*1}=-1+sqrt{17};\ x_2=-1-sqrt{17};\ y_1=2-(-1+sqrt{17})=3-sqrt{17};\ y_2=2-(-1-sqrt{17})=3+sqrt{17};\ (-1+sqrt{17};3-sqrt{17}); (-1-sqrt{17};3+sqrt{17})$