Question

как решать систему уравнений 2-3x=2(1-y) и 4(x+y)=x-1.5

Answer 1

$left { {{2-3x=2(1-y)} atop {4(x+y)=x-1.5}} right.$

$left { {{2-3x=2-2y} atop {4x+4y=x-1.5}} right.$

$left { {{-3x=-2y} atop {3x+4y=-1.5}} right.$

$left { {{-3x+2y=0} atop {3x+4y=-1.5}} right.$

$left { {{6y=-1.5} atop {3x+4y=-1.5}} right.$

$left { {{y=-1.5:6} atop {3x+4y=-1.5}} right.$

$left { {{y=-0.25} atop {3x+4*(-0.25)=-1.5}} right.$

$left { {{y=-0.25} atop {3x-1=-1.5}} right.$

$left { {{y=-0.25} atop {3x=-0.5}} right.$

$left { {{y=-0.25} atop {x=-0.5:3}} right.$

$left { {{y=-0.25} atop {x=- frac{1}{6} }} right.$

Ответ: $(- frac{1}{6};-0.25)$