Предмет: Химия, автор: tverdoxlebovda

Какое количество бутана (С4Н10) нужно взять, чтобы объём при нормальных условиях составил 0,224л?

Ответы

Автор ответа: simona6432

n = V/V(m) = 0,224 л/22,4 л/моль = 0,01 моль

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