Question

Решить системы 2 И 3 ИСПОЛЬЗУЯ ФОТО ИЛИ СТРОКУ ФОРМУЛ

Answer 1

$left { {{5^{x+2y}=1} atop {lg(x-3)=lg(2y+5)}} right. ; ;; ; ODZ:; left { {{x textgreater 3} atop {y textgreater -frac{5}{2}}} right. \\ left { {{x+2y=0} atop {x-3=2y+5}} right. ; left { {{x+2y=0} atop {x-2y=8}} right. ; left { {{x=-2y} atop {2x=8}} right. ; left { {{y=-2} atop {x=4}} right. \\Otvet:; (4,-2).$

$3); left { {{log_3x+log_3y=1} atop {y-3x=8}} right. ; ; ODZ:; x textgreater 0,; y textgreater 0\\ left { {{xy=3} atop {y=3x+8}} right. ; left { {{3x^2+8x-3=0} atop {y=3x+8}} right. ; left { {{x_1=-3,; x_2=frac{1}{3}} atop {y_1=-1,; y_2=9}} right. \\Otvet:; (frac{1}{3};9).$