Question

(2х-1)*(3х+4)-6хво 2 степени=16

Answer 1

$(2x-1)(3x+4)-6x^2=16\\ 6x^2-3x+8x-4-6x^2-16=0\\ 5x-20=0\\ 5x=20\\ x= frac{20}{5}\\ x=4$