Question

Помогите решить 5 и 6 номер. 50 баллов за ответ. Срочно!!!

Answer 1

$sqrt[3]{27}-sqrt[4]{81}+frac{2}{sqrt5-sqrt3}-sqrt[4]{25}-sqrt[4]9=\\=sqrt[3]{3^3}-sqrt[4]{3^4}+frac{2(sqrt5+sqrt3)}{5-3}-sqrt[4]{5^2}-sqrt[4]{3^2}=\\=3-3+sqrt5+sqrt3-sqrt5-sqrt3=0\\\x=sqrt[3]{4^4}; ,; ; sqrt[4]{xsqrt[3]{xsqrt{x}}}}=(xsqrt[3]{xsqrt{x}})^{frac{1}{4}}=x^{frac{1}{4}}((xsqrt{x})^{frac{1}{3}})^{frac{1}{4}}=\\=x^{frac{1}{4}}cdot x^{frac{1}{12}}cdot (x^{frac{1}{2}})^{frac{1}{12}}=x^{frac{1}{4}+frac{1}{12}+frac{1}{24}}=x^{frac{9}{24}}=$

$=(sqrt[3]{4^4})^{frac{9}{24}}=(4^{frac{4}{3}})^{frac{3}{8}}=4^{frac{1}{2}}=sqrt4=2$